document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=563839>Question 563839</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is six times its width. <BR>\n" );
document.write( "If the area of the rectangle is 600in squared , find its perimeter. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365116 by </B><A HREF=/tutors/aboutme.mpl?userid=bluemockingjay7><B>bluemockingjay7(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bluemockingjay7><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=bluemockingjay7><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 6w<BR>\n" );
document.write( "W = w\r<BR>\n" );
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document.write( "Area of the rectangle = lw\r<BR>\n" );
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document.write( "6w(w) = 600<BR>\n" );
document.write( "6w^2 = 600<BR>\n" );
document.write( "w^2 = 100<BR>\n" );
document.write( "w = square root of 100<BR>\n" );
document.write( "w = 10\r<BR>\n" );
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document.write( "L = 6(10) = 60in<BR>\n" );
document.write( "W = 10in\r<BR>\n" );
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document.write( "Perimeter of a rectangle: 2(L + W)\r<BR>\n" );
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document.write( "P = 2(60 + 10)<BR>\n" );
document.write( "P = 2(70)<BR>\n" );
document.write( "P - 140in </SPAN>\n" );
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