document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=563819>Question 563819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two trains are 330 miles apart, and their speeds differ by 200 mph. They travel toward each other and meet in 3 hours. Find the speed of each train.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #365079 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=365079\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Train A x mph<BR>\n" );
document.write( "Train B = x+20 mph\r<BR>\n" );
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document.write( "they are moving against each other<BR>\n" );
document.write( "add up speeds the effective speed = 2x+20\r<BR>\n" );
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document.write( "d=330 miles<BR>\n" );
document.write( "t= d/r<BR>\n" );
document.write( "3=330/(x+20)<BR>\n" );
document.write( "3(x+20)=330<BR>\n" );
document.write( "3x+60=330<BR>\n" );
document.write( "3x=270<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "x= 90 mph\r<BR>\n" );
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document.write( "Train A speed = 90 mph<BR>\n" );
document.write( "Train B speed = 90+20 =110 mph </SPAN>\n" );
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