document.write( "Question 563740: f(x)=25x^2+10x+1
\n" ); document.write( "type an ordered pair
\n" ); document.write( "I got 1 for y
\n" ); document.write( "I got -1/5 for x
\n" ); document.write( "The answer isn't an ordered pair though.
\n" ); document.write( "Could someone please help me out.
\n" ); document.write( "Thank You
\n" ); document.write( "

Algebra.Com's Answer #365055 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
\"f%28x%29+=+25x%5E2%2B10x%2B1\" Rewrite this as:
\n" ); document.write( "\"y+=+25x%5E2%2B10x%2B1\"
\n" ); document.write( "To get y = 1 as you did, you must have let x = 0, why? because:
\n" ); document.write( "\"y+=+25%280%296%2B10%280%29%2B1\"
\n" ); document.write( "\"y+=+1\"
\n" ); document.write( "So the ordered pair is: (0, 1)
\n" ); document.write( "And if you solved this quadratic equation, you would get:
\n" ); document.write( "\"y+=+25x%5E2%2B10x%2B1\" Set y = 0.
\n" ); document.write( "\"25x%5E2%2B10x%2B1+=+0\" Factor the left side.
\n" ); document.write( "\"%285x%2B1%29%285x%2B1%29+=+0\" so...
\n" ); document.write( "\"x+=+-1%2F5\" which is a double solution.
\n" ); document.write( "So when \"y+=+0\", \"x+=+-1%2F5\", the ordered pair would be: (\"-1%2F5\",\"0\")
\n" ); document.write( "But note that there is an infinite number of ordered pairs that satisfy this equation.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );