document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53790>Question 53790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me on this problem?\r<BR>\n" );
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document.write( "  I need to identify the rate, base, and amount in the following application.  You do not need to solve the applications at this point.\r<BR>\n" );
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document.write( "   A chemist has 300 milliliters (mL) of solution that is 18% acid.  How many milliliters of acid are in the solution?\r<BR>\n" );
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document.write( "  Thanks,  Ashley </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36502 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36502\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 18%=.18 THEN .18*300ML=54 ML OF ACID OR 54/300=.18 OR 18%  </SPAN>\n" );
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