document.write( "Question 563466: David is the age of 58 and Lisa is the age of 18. How long ago was David 5 times the age of Lisa.\r
\n" ); document.write( "\n" ); document.write( "Logically, I know the answer is 8 years ago since David would have been 50 and Lisa would have been 10 and 5*10 =50 which five times her age.\r
\n" ); document.write( "\n" ); document.write( "However, I need to come with this answer in an algebraic method and I've been wracking my brain over it.
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Algebra.Com's Answer #365004 by ankor@dixie-net.com(22740)\"\" \"About 
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David is the age of 58 and Lisa is the age of 18.
\n" ); document.write( "How long ago was David 5 times the age of Lisa.
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\n" ); document.write( "let y = the no. years ago that D was 5 times L's age
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\n" ); document.write( "58 - y = 5(18-y)
\n" ); document.write( "58 - y = 90 - 5y
\n" ); document.write( "-y + 5y = 90 - 58
\n" ); document.write( "4y = 32
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