document.write( "Question 563572: Eight years ago, Heather was twice as old as her brother David. Today she is 13 years older than him. How old is she? \n" ); document.write( "
Algebra.Com's Answer #364936 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=David's current age; x-8=David's age 8 years ago \n" ); document.write( "Then x+13=Heather's current age; x+13-8=x+5=Heather's age 8 years ago \n" ); document.write( "Soooooo \n" ); document.write( "x+5=2(x-8)get rid of parens \n" ); document.write( "x+5=2x-16 subtract 2x and also 5 from each side \n" ); document.write( "-x=-21 \n" ); document.write( "x=21----David's current age \n" ); document.write( "x+13=21+13=34----Heather's current age\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "Today: 21+13=34 ok \n" ); document.write( "8 years ago: 34-8=2(21-8) \n" ); document.write( "26=2*13 ok\r \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " |