document.write( "Question 563567: Kathi and Robert Hawn had a pottery stand at the annual skipcack craft fair. They sold some of their pottery at the original price of $9.50 for each piece, but later decreased the price by $2. If they sold all 90 pieces and took in $713, find how many pieces they sold at the original price and how many pieces they sold at the reduced price? \n" ); document.write( "
Algebra.Com's Answer #364933 by mananth(16946)\"\" \"About 
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let them sell x pieces at $9.50
\n" ); document.write( "and y pieces at $7.50\r
\n" ); document.write( "\n" ); document.write( "x+y=90
\n" ); document.write( "9.5x+7.5y=713\r
\n" ); document.write( "\n" ); document.write( "$9.50 x numbers
\n" ); document.write( "$7.50 y numbers
\n" ); document.write( "
\n" ); document.write( "1 x + 1 y = 90 .............1
\n" ); document.write( "9.5 x + 7.5 y = 713 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -7.5
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-7.5 x -7.5 y = -675
\n" ); document.write( "9.5 x 7.5 y = 713
\n" ); document.write( "Add the two equations
\n" ); document.write( "2 x = 38
\n" ); document.write( "/ 2
\n" ); document.write( "x = 19
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1 x + 1 y = 90
\n" ); document.write( "19 + 1 y = 90
\n" ); document.write( " 1 y = 90 -19
\n" ); document.write( " 1 y = 71
\n" ); document.write( " y = 71
\n" ); document.write( "$9.50 19 numbers
\n" ); document.write( "$7.50 71 numbers
\n" ); document.write( "m.ananth@hotmail.ca
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