document.write( "Question 563566: Solve for x:\r
\n" ); document.write( "\n" ); document.write( "\"a%5E2x%5E2+%2B+2ax+%2B+1+=+0\"
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Algebra.Com's Answer #364932 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
\"a%5E2x%5E2+%2B+2ax+%2B+1+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28ax%2B1%29%5E2=0\"\r
\n" ); document.write( "\n" ); document.write( "take the square root
\n" ); document.write( "ax+1= 0
\n" ); document.write( "ax=-1
\n" ); document.write( "x=-1/a
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