document.write( "Question 563498: Phil had 50 nickels and dimes worth $4.15. How many dimes does he have. \n" ); document.write( "
Algebra.Com's Answer #364900 by Maths68(1474)\"\" \"About 
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Total worth = $4.15 = 4.15*100 = 415 cents
\n" ); document.write( "Total Coins = 50
\n" ); document.write( "Total Dimes = x
\n" ); document.write( "Total Nickel = 50-x
\n" ); document.write( "One Dime = d = 10 cents
\n" ); document.write( "One Nickel = n = 5 cents\r
\n" ); document.write( "\n" ); document.write( "Dime*x+Nickel*(50-x)=Total worth
\n" ); document.write( "10*x+5(50-x)=415
\n" ); document.write( "10x+250-5x=415
\n" ); document.write( "5x=415-250
\n" ); document.write( "5x=165
\n" ); document.write( "5x/5=165/5
\n" ); document.write( "x=33\r
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\n" ); document.write( "\n" ); document.write( "Total Dimes = x = 33
\n" ); document.write( "Total Nickel = 50-x = 50-33 = 17\r
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\n" ); document.write( "10*33+5*17=415
\n" ); document.write( "330+85=415
\n" ); document.write( "415=415\r
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