document.write( "Question 563498: Phil had 50 nickels and dimes worth $4.15. How many dimes does he have. \n" ); document.write( "
Algebra.Com's Answer #364900 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Total worth = $4.15 = 4.15*100 = 415 cents \n" ); document.write( "Total Coins = 50 \n" ); document.write( "Total Dimes = x \n" ); document.write( "Total Nickel = 50-x \n" ); document.write( "One Dime = d = 10 cents \n" ); document.write( "One Nickel = n = 5 cents\r \n" ); document.write( "\n" ); document.write( "Dime*x+Nickel*(50-x)=Total worth \n" ); document.write( "10*x+5(50-x)=415 \n" ); document.write( "10x+250-5x=415 \n" ); document.write( "5x=415-250 \n" ); document.write( "5x=165 \n" ); document.write( "5x/5=165/5 \n" ); document.write( "x=33\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Total Dimes = x = 33 \n" ); document.write( "Total Nickel = 50-x = 50-33 = 17\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "========= \n" ); document.write( "10*33+5*17=415 \n" ); document.write( "330+85=415 \n" ); document.write( "415=415\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |