document.write( "Question 563449: Find three consecutive integers such that the sum of the first plus one-third of the second plus three-eighths of the third is 25. \n" ); document.write( "
Algebra.Com's Answer #364882 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "First Number = \n" ); document.write( "Second Number= \n" ); document.write( "Third Number = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given \n" ); document.write( "======= \n" ); document.write( "sum of the first plus one-third of the second plus three-eighths of the third is 25. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take LCD on R.H.S. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply by 24 both sides of above equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Divide by 41 both sides of above equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First Number = \n" ); document.write( "Second Number= \n" ); document.write( "Third Number = \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "====== \n" ); document.write( "sum of the first plus one-third of the second plus three-eighths of the third is 25. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |