document.write( "Question 563390: how do you show the equation of a line that passes through point (0, b)and (1,b + m)is y=mx+b and how do you explain that point (-1, b -m) also is on the line?
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Algebra.Com's Answer #364862 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
(0,b) (1,b+m)are the points\r
\n" ); document.write( "\n" ); document.write( "(b+m-b)/1 = m is the slope\r
\n" ); document.write( "\n" ); document.write( "The equation of line
\n" ); document.write( "(y-y1)= m(x-x1)\r
\n" ); document.write( "\n" ); document.write( "plug (0,b) & m in the equation\r
\n" ); document.write( "\n" ); document.write( "(y-b)=m(x-0)\r
\n" ); document.write( "\n" ); document.write( "y-b=mx\r
\n" ); document.write( "\n" ); document.write( "y=mx+b\r
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\n" ); document.write( "\n" ); document.write( "substitute -1, b-m in the equation y= mx+b\r
\n" ); document.write( "\n" ); document.write( "b-m = m*-1+b\r
\n" ); document.write( "\n" ); document.write( "b-m = b-m\r
\n" ); document.write( "\n" ); document.write( "so the point is on the line \r
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