document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=563321>Question 563321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of the expression. Do not use decimals.<BR>\n" );
document.write( "(1/3)log54+2log15+(1/3)log32-3log3\r<BR>\n" );
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document.write( "All the bases are 10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364842 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/3)log54+2log15+(1/3)log32-3log3 <BR>\n" );
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document.write( "log(2*27)^(1/3) + log(15^2) + log(8*4)^(1/3) - log(3^3)<BR>\n" );
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document.write( "= log(3*2^(1/3)) + log(225) + log(2*4^(1/3)) - log(27)<BR>\n" );
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document.write( "= log[3*2^(1/3)*225*2*4^(1/3)/27]<BR>\n" );
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document.write( "= log[1350*8^(1/3)/27]<BR>\n" );
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document.write( "= log[2700/27]<BR>\n" );
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document.write( "= log(100)<BR>\n" );
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document.write( "= 10<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "===================== </SPAN>\n" );
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