document.write( "Question 562902: Solve\r
\n" ); document.write( "\n" ); document.write( "log5 3^x = log25 9^(1-2x)
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Algebra.Com's Answer #364769 by lwsshak3(11628)\"\" \"About 
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log5 3^x = log25 9^(1-2x)
\n" ); document.write( "convert to log base 10
\n" ); document.write( "log(3^x)/log(5)=log(9^(1-2x))/log25
\n" ); document.write( "log25=log5^2=2log5
\n" ); document.write( "log(3^x)/log(5)=log(9^(1-2x))/2log5
\n" ); document.write( "2log(3^x)=log(9^(1-2x)
\n" ); document.write( "log(3^2x)=log(9^(1-2x)
\n" ); document.write( "(3^2x)=(9^(1-2x)
\n" ); document.write( "(3^2x)=(3^(2(1-2x))
\n" ); document.write( "3^2x=3^(2-4x)
\n" ); document.write( "2x=2-4x
\n" ); document.write( "6x=2
\n" ); document.write( "x=1/3
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