document.write( "Question 562902: Solve\r
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document.write( "log5 3^x = log25 9^(1-2x) \n" );
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Algebra.Com's Answer #364769 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! log5 3^x = log25 9^(1-2x) \n" ); document.write( "convert to log base 10 \n" ); document.write( "log(3^x)/log(5)=log(9^(1-2x))/log25 \n" ); document.write( "log25=log5^2=2log5 \n" ); document.write( "log(3^x)/log(5)=log(9^(1-2x))/2log5 \n" ); document.write( "2log(3^x)=log(9^(1-2x) \n" ); document.write( "log(3^2x)=log(9^(1-2x) \n" ); document.write( "(3^2x)=(9^(1-2x) \n" ); document.write( "(3^2x)=(3^(2(1-2x)) \n" ); document.write( "3^2x=3^(2-4x) \n" ); document.write( "2x=2-4x \n" ); document.write( "6x=2 \n" ); document.write( "x=1/3 \n" ); document.write( " |