document.write( "Question 563088: My question is |x-2| < 1/2
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Algebra.Com's Answer #364766 by Edwin McCravy(20060) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Rules:\r\n" );
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document.write( "        If C is a positive number, then\r\n" );
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document.write( "  |Ax+B| < C           |             |Ax+B| > C \r\n" );
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document.write( "is equivalent to       |          is equivalent to\r\n" );
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document.write( " -C < Ax+B < C         |        Ax+B < -C  OR Ax+B > C\r\n" );
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document.write( "       [Same rules for < and >]\r\n" );
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document.write( " |x-2| < \r\n" );
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document.write( "is equivalent to\r\n" );
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document.write( " < x-2 < \r\n" );
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document.write( "Multiply all three sides by 2\r\n" );
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document.write( "     -1 < 2x-4 < 1\r\n" );
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document.write( "Add 4 to all three sides:\r\n" );
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document.write( "  -1+4 < 2x-4+4 < 1+4\r\n" );
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document.write( "       3 < 2x < 5\r\n" );
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document.write( "Divide all three sides by 2\r\n" );
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document.write( "       <  < \r\n" );
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document.write( "       < x < \r\n" );
document.write( "    \r\n" );
document.write( "Interval notation is\r\n" );
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document.write( "         (, )\r\n" );
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document.write( "Edwin

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