document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562913>Question 562913</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a question. what do you do if you need to prove a triangle is a right triangle, but you only have variable coordinates for that triangle. Here's what I have so far: Triangle ABC: A(x,0); B(x,y); C(2x,0)<BR>\n" );
document.write( "Finding AB: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%28x-x%29%5E2%2B%28y-0%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%28x-x%29%5E2%2B%28y-0%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282y%29 ALIGN=MIDDLE  ALT=\"sqrt%282y%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Finding BC: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%282x-x%29%5E2%2B%280-y%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%282x-x%29%5E2%2B%280-y%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%5E2=y%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28x%5E2=y%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Finding AC: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%282x-x%29%5E2%2B%280-0%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%282x-x%29%5E2%2B%280-0%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Final Steps: a^2+b^2=c^2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%282y%29%29%5E2%2B+sqrt%28%28x%5E2%29%29%5E2=+sqrt%28%28x%5E2%2By%5E2%29%29%5E2 ALIGN=MIDDLE  ALT=\"sqrt%28%282y%29%29%5E2%2B+sqrt%28%28x%5E2%29%29%5E2=+sqrt%28%28x%5E2%2By%5E2%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%284y%5E2%29%2B+sqrt%282x%5E4%29=+sqrt%28x%5E4%2By%5E4%29 ALIGN=MIDDLE  ALT=\"sqrt%284y%5E2%29%2B+sqrt%282x%5E4%29=+sqrt%28x%5E4%2By%5E4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "I'm confused on what to do next. I know that if a^2+b^2=c^2 then it is a right triangle. But, I can't solve it any furthur. I also can't use sin, cos, or tan. Thannk you in advance.   <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364740 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364740\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Triangle ABC: A(x,0); B(x,y); C(2x,0)<BR>\n" );
document.write( "Finding AB: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%28x-x%29%5E2%2B%28y-0%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%28x-x%29%5E2%2B%28y-0%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28y%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28y%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "=y<BR>\n" );
document.write( "Finding BC: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%282x-x%29%5E2%2B%280-y%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%282x-x%29%5E2%2B%280-y%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%5E2%2By%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28x%5E2%2By%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Finding AC: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%282x-x%29%5E2%2B%280-0%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%282x-x%29%5E2%2B%280-0%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28x%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28x%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "=x<BR>\n" );
document.write( "Final Steps: a^2+b^2=c^2\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%28x%5E2%29%29%5E2%2B%28sqrt%28y%5E2%29%29%5E2=+%28sqrt%28x%5E2%2By%5E2%29%29%5E2 ALIGN=MIDDLE  ALT=\"%28sqrt%28x%5E2%29%29%5E2%2B%28sqrt%28y%5E2%29%29%5E2=+%28sqrt%28x%5E2%2By%5E2%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );