document.write( "Question 562313: Alex's age is 3 year more than twice Vincent's age. in 4 years, the sum of their age is 58.
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Algebra.Com's Answer #364730 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Alex = a \n" ); document.write( "Present age of Vincent = v\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given \n" ); document.write( "======= \n" ); document.write( "Alex's age is 3 year more than twice Vincent's age \n" ); document.write( "a=2v+3...........(1) \n" ); document.write( "In 4 years \n" ); document.write( "Alex will be = a+4 \n" ); document.write( "Vincent will be = v+4 \n" ); document.write( "Then \n" ); document.write( "the sum of their age is 58 \n" ); document.write( "a+4+v+4=58 \n" ); document.write( "a+v+8=58 \n" ); document.write( "a+v=58-8 \n" ); document.write( "a+v=50.............(2) \n" ); document.write( "Put the value of a from (1) to (2) \n" ); document.write( "2v+3+v=50 \n" ); document.write( "3v=50-3 \n" ); document.write( "3v=47 \n" ); document.write( "3v/3=47/3 \n" ); document.write( "v=15.66 \n" ); document.write( "Put the value of v in (1) \n" ); document.write( "a=2v+3...........(1) \n" ); document.write( "a=2(15.66)+3 \n" ); document.write( "a=31.33+3 \n" ); document.write( "a=34.33\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present age of Alex = a = 34.33 years old (approximately 34 years 3 months 28 days) \n" ); document.write( "Present age of Vincent = v = 15.66 years old (approximately 15 years 7 months 27 days) \n" ); document.write( " |