document.write( "Question 562796: Find three consecutive integers such that the first plus three times the third is 10 less than three times the second. \n" ); document.write( "
Algebra.Com's Answer #364712 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "First Number = \"x%2B1\"
\n" ); document.write( "Second Number=\"x%2B2\"
\n" ); document.write( "Third Number = \"x%2B3\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B1%2B3%28x%2B3%29=3%28x%2B2%29-10\"
\n" ); document.write( "\"x%2B1%2B3x%2B9=3x%2B6-10\"
\n" ); document.write( "\"4x%2B10=3x%2B6-10\"
\n" ); document.write( "\"4x=3x%2B6-10-10\"
\n" ); document.write( "\"4x=3x%2B6-20\"
\n" ); document.write( "\"4x-3x=-14\"
\n" ); document.write( "\"x=-14\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "First Number = \"x%2B1\" = \"-14%2B1\" = \"-13\"
\n" ); document.write( "Second Number=\"x%2B2\" = \"-14%2B2\" = \"-12\"
\n" ); document.write( "Third Number = \"x%2B3\" = \"-14%2B3\" = \"-11\"\r
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