document.write( "Question 562787: Please help me solve this:
\n" ); document.write( "2^-x=1.5
\n" ); document.write( "I tried this:
\n" ); document.write( "ln2^-x=ln1.5
\n" ); document.write( "-xln2=ln1.5
\n" ); document.write( "-x=ln1.5/ln2
\n" ); document.write( "x=-0.585
\n" ); document.write( "Thanks \n" ); document.write( "

Algebra.Com's Answer #364694 by issacodegard(60) $\"\"$ $\"About$

You can put this solution on YOUR website!
Yep, that's right! \n" ); document.write( "

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