document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562778>Question 562778</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need to find the dimension of a rectangle with a perimeter of 640yds. All I have is one side is w and the other is 3w-12. 3w has me confused. Thanks.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364683 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364683\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2w+2(3w-12)=640<BR>\n" );
document.write( "2w+6w-24=640<BR>\n" );
document.write( "8w=640+24<BR>\n" );
document.write( "8w=684<BR>\n" );
document.write( "w=684/8<BR>\n" );
document.write( "w=85.5<BR>\n" );
document.write( "L=(3w-12)=3*85.5-12<BR>\n" );
document.write( "L=244.5 </SPAN>\n" );
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