document.write( "Question 562747: Academic Calculus- Pythagorean Theorem and Related Rates Word Problem:\r
\n" );
document.write( "\n" );
document.write( "A plane takes off from airport A and flies east at 480 mph. At the moment of takeoff, a second plane, approaching A from the north at 320 mph, is still 240 miles from A. Fifteen minutes later is the distance between the planes increasing or decreasing, and how fast? \n" );
document.write( "
Algebra.Com's Answer #364671 by issacodegard(60)![]() ![]() You can put this solution on YOUR website! Hi, let A=(0,0). Then, the second plane starts at (0,240). Let x(t) be the distance from A to plane 1 at time t, y(t) be the distance from A to plane 2 at time 2, and z(t) be the distance between the planes at time t (I say distance because I know that plane two doesn't reach the airport in 15 minutes). We know, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So by implicit differentiation, \n" ); document.write( " \n" ); document.write( "So at time t=1/4 hr, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So, we get \n" ); document.write( " \n" ); document.write( "This is positive, so the distance between them is increasing, so the planes are getting further away at a rate of 32mph. \n" ); document.write( " |