document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562702>Question 562702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need dimensions of a rectangle with a 380m perimeter. I dont understand the explanation my daughter got at school. Here is what she has written.<BR>\n" );
document.write( "w+w+20+w+w+20=380<BR>\n" );
document.write( "4w+40=380<BR>\n" );
document.write( "-40=340<BR>\n" );
document.write( "4w=340<BR>\n" );
document.write( "340 divided by 4=85<BR>\n" );
document.write( "4w=85<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364651 by </B><A HREF=/tutors/aboutme.mpl?userid=issacodegard><B>issacodegard(60)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=issacodegard><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=issacodegard><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi, it looks like she was also given the information that the dimensions differ by 20, like the length is 20 more than the width.  So one dimension is w and the other is w+20 (knowing only the perimeter is not enough to determine the dimensions uniquely).  So the first line would look like,<BR>\n" );
document.write( "w+(w+20)+w+(w+20)=380<BR>\n" );
document.write( "Solve for w:<BR>\n" );
document.write( "4w+40=380<BR>\n" );
document.write( "4w=340   (subtract 40)<BR>\n" );
document.write( "w=85   (divide by 4)<BR>\n" );
document.write( "One dimension is w=85, and the other dimension is w+20=85+20=105. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );