document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562689>Question 562689</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Having trouble can't remember how to work this problem out.<BR>\n" );
document.write( "4(5n-7)=32<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364648 by </B><A HREF=/tutors/aboutme.mpl?userid=issacodegard><B>issacodegard(60)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=issacodegard><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=issacodegard><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi, first we distribute the 4 to get,<BR>\n" );
document.write( "4*5n-4*7=32<BR>\n" );
document.write( "20n-28=32<BR>\n" );
document.write( "Add 28 to both sides:<BR>\n" );
document.write( "20n-28+28=32+28<BR>\n" );
document.write( "20n=60<BR>\n" );
document.write( "Divide by 20 on both sides:<BR>\n" );
document.write( "20n/20=60/20<BR>\n" );
document.write( "n=3 </SPAN>\n" );
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