document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562683>Question 562683</A>: <I><SPAN STYLE=\"word-break: break-all;\"> YWXZ is a rhombus with diagonals that intersect at point S. Angle WSX measures (3x+12). Find the value of X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364646 by </B><A HREF=/tutors/aboutme.mpl?userid=issacodegard><B>issacodegard(60)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=issacodegard><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=issacodegard><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By knowing that the diagonals of a rhombus are each other's perpendicular bisectors, we conclude that they intersect at right angles. So, angle WSX has measure 90 degrees.  So, we solve 3x+12=90 for x, which gives us x=26. </SPAN>\n" );
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