document.write( "Question 562507: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 miles per hour and train B is traveling at 80miles per hour. Train A passes a station @ 12:10am. If train B passes the same station @ 12:22am, at what time will train B catch up to train A?\r
\n" ); document.write( "\n" ); document.write( "I am not sure how to right the equation to solve, help?!! If you could please provide the equation and the answer so I can check my work? \r
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Algebra.Com's Answer #364600 by ankor@dixie-net.com(22740)\"\" \"About 
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Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 miles per hour and train B is traveling at 80miles per hour. Train A passes a station @ 12:10am. If train B passes the same station @ 12:22am, at what time will train B catch up to train A?
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\n" ); document.write( "From the given information, we know that Train B is 12 min behind A at at 12:10 pm
\n" ); document.write( "therefore Train B is:
\n" ); document.write( "\"12%2F60\" * 80 = 16 miles behind Train A at that time.
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\n" ); document.write( "Let t = time required for Train B to catch Train A
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\n" ); document.write( "Write a distance equation; dist = speed * time
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\n" ); document.write( "Train B dist = Train A dist + 16 mi
\n" ); document.write( "80t = 60t + 16
\n" ); document.write( "80t - 60t = 16
\n" ); document.write( "20t = 16
\n" ); document.write( "t = \"16%2F20\"
\n" ); document.write( "t = .8 hrs for B to catch A
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\n" ); document.write( "Convert .8 hrs to minutes: .8(60) = 48 min
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\n" ); document.write( "Find the time from 12:10 pm:
\n" ); document.write( "12:10 + 0:48 = 12:58 pm, Train B catches Train A
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