document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562463>Question 562463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x+y=5     In this I do not understand how to get 5 on the other side and y by itself. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364587 by </B><A HREF=/tutors/aboutme.mpl?userid=MathHelper7><B>MathHelper7(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathHelper7><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathHelper7><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364587\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Very simple.<BR>\n" );
document.write( "Add -2x by both sides:<BR>\n" );
document.write( "   2x+y=5<BR>\n" );
document.write( "  -2x  -2x<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "   y=5+-2x\r<BR>\n" );
document.write( "\n" );
document.write( "There you go! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );