document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562474>Question 562474</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of two supplementary angles are in the ratio 1:4. What are the measure of the angles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364575 by </B><A HREF=/tutors/aboutme.mpl?userid=jlshires><B>jlshires(17)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jlshires><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If two angles are supplementary it means they add up to 180 degrees (ie they make a straight line.) \r<BR>\n" );
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document.write( "If the ratio of both angles is 1:4, then that means the bigger angle is four times the size of the smaller. Using that, you can add variables. The smaller andle is x (or 1x) and the bigger one would be four times that, so 4x. If you add the two angles together, you get 180.\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "x+4x=180<BR>\n" );
document.write( "5x=180<BR>\n" );
document.write( "divide both side by 5 to get\r<BR>\n" );
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document.write( "x=36\r<BR>\n" );
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document.write( "substitute this in for your original formulas of x and 4x\r<BR>\n" );
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document.write( "x=36, the smaller angle is 36 degrees<BR>\n" );
document.write( "4x= 4(36)= 144, the larger angle is 144 degrees </SPAN>\n" );
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