document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562373>Question 562373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the area between the x-axis, the vertical lines x = 0 and x = 1 and the following curve:\r<BR>\n" );
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document.write( "F(x) = 2x^3 + e^3x\r<BR>\n" );
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document.write( "Please, thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364559 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Determine the area between the x-axis, the vertical lines x = 0 and x = 1 and the following curve:\r<BR>\n" );
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document.write( "F(x) = 2x^3 + e^3x<BR>\n" );
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document.write( "F+(1) = 1/2 + e^3/3<BR>\n" );
document.write( "F+(0) = 1/3<BR>\n" );
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document.write( "Area = F+(1) - F+(0) = 1/2 + e^3/3 - 1/3<BR>\n" );
document.write( "Area =~ 6.8618 sq units<BR>\n" );
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document.write( "F+(x) also has a C term, the constant, but they cancel when the 2 values are subtracted, so they can be ignored.<BR>\n" );
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