document.write( "Question 562342: write the equation of the line that is parallel to the line y=-3+12 and passes through the point (-1,6) \n" ); document.write( "

Algebra.Com's Answer #364551 by mananth(16946) $\"\"$ $\"About$

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1 y = -3 x + 12
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = -3 x + 12
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = -3 0.8
\n" ); document.write( "The slope of a line parallel to the above line will be the same
\n" ); document.write( "The slope of the required line will be -3
\n" ); document.write( "m= -3 ,point (-1,6 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "6 = 3 + b
\n" ); document.write( "b= 3
\n" ); document.write( "m= -3
\n" ); document.write( "Plug value of the slope and b in y = mx +b
\n" ); document.write( "The required equation is y= -3x + 3
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\n" ); document.write( "m.ananth@hotmail.ca
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