document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562342>Question 562342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the equation of the line that is parallel to the line y=-3+12 and passes through the point (-1,6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364550 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I think you meant:<BR>\n" );
document.write( "y=-3x+12<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If so, the slope of the line above is -3<BR>\n" );
document.write( "If the new line is parallel, it must have the same slope.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Plug the slope (-3) and the given point (-1,6) into the \"point-slope\" form:<BR>\n" );
document.write( "y - y1 = m(x - x1)<BR>\n" );
document.write( "y - 6 = -3(x - (-1))<BR>\n" );
document.write( "y - 6 = -3(x + 1)<BR>\n" );
document.write( "y - 6 = -3x - 3<BR>\n" );
document.write( "y = -3x + 3 (this is what they're looking for)\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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