document.write( "Question 562282: at 7:00 am joe starts jogging at 6mi/h . At 7:10 Ken starts off after him. How fast must ken run in order to overtake him at 7:30 \n" ); document.write( "
Algebra.Com's Answer #364525 by lwsshak3(11628) ![]() You can put this solution on YOUR website! at 7:00 am joe starts jogging at 6mi/h . At 7:10 Ken starts off after him. How fast must ken run in order to overtake him at 7:30 \n" ); document.write( "** \n" ); document.write( "let x=ken's speed (mph) \n" ); document.write( "ken's travel time=7:30-7:10=20 min=1/3 hr \n" ); document.write( "joe's speed=6 mph \n" ); document.write( "joe's travel time=7:30-7:00=30 min=1/2 hr \n" ); document.write( "Both runners covered the same distance \n" ); document.write( "distance=travel time*speed \n" ); document.write( "x*(1/3)=6*(1/2)=3 \n" ); document.write( "x=9 mph \n" ); document.write( "ans: \n" ); document.write( "How fast must ken run in order to overtake him at 7:30=9 mph \n" ); document.write( " |