document.write( "Question 562272: twice a number increased by 11 is 21 less than three times the number. \n" ); document.write( "
Algebra.Com's Answer #364519 by Maths68(1474)\"\" \"About 
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Let x be the number\r
\n" ); document.write( "\n" ); document.write( "Twice the x = 2x
\n" ); document.write( "Three times the x = 3x
\n" ); document.write( "Twice the x increased by 11 = 2x+11
\n" ); document.write( "21 less than three times the x = 3x-21\r
\n" ); document.write( "\n" ); document.write( "2x+11=3x-21
\n" ); document.write( "2x-3x=-21-11
\n" ); document.write( "-x=-32
\n" ); document.write( "Multiply by -1 both sides of above equation
\n" ); document.write( "-x(-1)=-32(-1)
\n" ); document.write( "x=32\r
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\n" ); document.write( "\n" ); document.write( "Check
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\n" ); document.write( "2x+11=3x-21
\n" ); document.write( "Put the value of x in above equation
\n" ); document.write( "2(32)+11=3(32)-21
\n" ); document.write( "64+11=96-21
\n" ); document.write( "75= 75
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