document.write( "Question 562272: twice a number increased by 11 is 21 less than three times the number. \n" ); document.write( "
Algebra.Com's Answer #364519 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let x be the number\r \n" ); document.write( "\n" ); document.write( "Twice the x = 2x \n" ); document.write( "Three times the x = 3x \n" ); document.write( "Twice the x increased by 11 = 2x+11 \n" ); document.write( "21 less than three times the x = 3x-21\r \n" ); document.write( "\n" ); document.write( "2x+11=3x-21 \n" ); document.write( "2x-3x=-21-11 \n" ); document.write( "-x=-32 \n" ); document.write( "Multiply by -1 both sides of above equation \n" ); document.write( "-x(-1)=-32(-1) \n" ); document.write( "x=32\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "====== \n" ); document.write( "2x+11=3x-21 \n" ); document.write( "Put the value of x in above equation \n" ); document.write( "2(32)+11=3(32)-21 \n" ); document.write( "64+11=96-21 \n" ); document.write( "75= 75 \n" ); document.write( " \n" ); document.write( " |