document.write( "Question 562256: A chemist has three solutions of acid that must be mixed to obtain 20 liters of a solution that is 38% acid. Solution A is 30% acid, solution B is 20% acid and solution C is 60% acid. Because of another chemical in these solutions, the chemist must keep the ratio of solution C to solution A at 2 to 1. How many liters of each should she mix together?
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Algebra.Com's Answer #364508 by josmiceli(19441)\"\" \"About 
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given:
\n" ); document.write( "(1) \"+a+%2B+b+%2B+c+=+20+\"
\n" ); document.write( "\"+.38%2A20+=+7.6+\" liters of acid in mixture
\n" ); document.write( "(2) \"+.3a+%2B+.2b+%2B+.6c+=+7.6+\"
\n" ); document.write( "(3) \"+c%2Fa+=+2%2F1+\"
\n" ); document.write( "------------
\n" ); document.write( "(3) \"+c+=+2a+\"
\n" ); document.write( "(2) \"+3a+%2B+2b+%2B+6c+=+76+\"
\n" ); document.write( "Multiply both sides of (1) by \"+2+\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+3a+%2B+2b+%2B+6c+=+76+\"
\n" ); document.write( "(1) \"+-2a+-+2b+-+2c+=+40+\"
\n" ); document.write( "\"+a+%2B+4c+=+36+\"
\n" ); document.write( "Substitute (3) into this
\n" ); document.write( "\"+a+%2B+4%2A2a++=+36+\"
\n" ); document.write( "\"+9a+=+36+\"
\n" ); document.write( "\"+a+=+4+\"
\n" ); document.write( "and
\n" ); document.write( "(3) \"+c+=+2a+\"
\n" ); document.write( "(3) \"+c+=+2%2A4+\"
\n" ); document.write( "(3) \"+c+=+8+\"
\n" ); document.write( "(1) \"+a+%2B+b+%2B+c+=+20+\"
\n" ); document.write( "(1) \"+4+%2B+b+%2B+8+=+20+\"
\n" ); document.write( "(1) \"+b+=+20+-+12+\"
\n" ); document.write( "(1) \"+b+=+8+\"
\n" ); document.write( "4 liters of A
\n" ); document.write( "8 liters of B
\n" ); document.write( "8 liters of C are needed
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+.3a+%2B+.2b+%2B+.6c+=+7.6+\"
\n" ); document.write( "(2) \"+1.2+%2B+1.6+%2B+4.8++=+7.6+\"
\n" ); document.write( "(2) \"+7.6+=+7.6+\"
\n" ); document.write( "OK
\n" ); document.write( "(1) \"+a+%2B+b+%2B+c+=+20+\"
\n" ); document.write( "(1) \"+4+%2B+8+%2B+8+=+20+\"
\n" ); document.write( "(1) \"+20+=+20+\"
\n" ); document.write( "OK
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