document.write( "Question 562223: it takes a botat 2 hours to travel 20 miles down a river and 3 hours to return upstream to its starting point. what is the rate of the current in the river \n" ); document.write( "
Algebra.Com's Answer #364499 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! it takes a boat 2 hours to travel 20 miles down a river and 3 hours to return upstream to its starting point. what is the rate of the current in the river \n" ); document.write( "--------------------- \n" ); document.write( "Down River DATA: \n" ); document.write( "dist = 20 miles ; time = 2 hrs ; rate = d/t = 10 mph \n" ); document.write( "------- \n" ); document.write( "Up River DATA: \n" ); document.write( "dist = 20 miles : time = 3 hrs ; rate = d/t = 20/3 mph \n" ); document.write( "--------- \n" ); document.write( "Equation: \n" ); document.write( "b + c = 10 mph \n" ); document.write( "b - c = 20/3 mph \n" ); document.write( "------ \n" ); document.write( "2b = (10 + 20/3) = (50/3) \n" ); document.write( "--- \n" ); document.write( "b = 25/3 mph (speed of the boat in still water) \n" ); document.write( "---- \n" ); document.write( "Solve for \"c\": \n" ); document.write( "b + c = 10 \n" ); document.write( "(25/3) + c = (30/3) \n" ); document.write( "---- \n" ); document.write( "c = 5/3 = 1 2/3 mph (speed of the current) \n" ); document.write( "================================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " \n" ); document.write( " |