document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54174>Question 54174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Convert+equation+of+the+parabola+y=-6%5E2-6x+to+standard+form+and+then+find+the+product+a+x+h+x+k. ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36448 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Convert equation of the parabola y=-6^2-6x to standard form and then find the product a x h x k.}}} <BR>\n" );
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document.write( "Rewrite as:<BR>\n" );
document.write( "-6x^2-6x + ? = y+?<BR>\n" );
document.write( "-6(x^2+x + ? = y + ?<BR>\n" );
document.write( "(x^2+x+(1/4)) = (-1/6)(y)+(1/4)<BR>\n" );
document.write( "(x+(1/2))^2 = (-1/6)(y+(-6/4))<BR>\n" );
document.write( "(x+1/2)^2=-(1/6))(y-(3/2))<BR>\n" );
document.write( "h=(-1/2),k=(3/2)<BR>\n" );
document.write( "Standard form is y=ax^2+bx+c<BR>\n" );
document.write( "y=-6x^2-6x+0<BR>\n" );
document.write( "a=-6<BR>\n" );
document.write( "ahk=-6(-1/2)(3/2)=18/4=9/2<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );