document.write( "Question 561655: the sum of the digits of a 3-digit number is 14. the hundred's digit being four times the unit's digit. if 594 is subtracted from the number, the number will be reversed. \n" ); document.write( "
Algebra.Com's Answer #364462 by ankor@dixie-net.com(22740)\"\" \"About 
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Let a = the 100's digit
\n" ); document.write( "let b = the 10's
\n" ); document.write( "let c = the units
\n" ); document.write( "then
\n" ); document.write( "100a + 10b + c = the number
\n" ); document.write( ":
\n" ); document.write( "write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"the sum of the digits of a 3-digit number is 14.\"
\n" ); document.write( "a + b + c = 14
\n" ); document.write( ":
\n" ); document.write( "\"the hundred's digit being four times the unit's digit.\"
\n" ); document.write( "a = 4c
\n" ); document.write( ":
\n" ); document.write( "\" if 594 is subtracted from the number, the number will be reversed.\"
\n" ); document.write( "100a + 10b + c - 594 = 100c + 10b + a
\n" ); document.write( "100a - a + 10b - 10b = 100c - c + 594
\n" ); document.write( "99a = 99c + 594
\n" ); document.write( "simplify, divide by 99
\n" ); document.write( "a = c + 6
\n" ); document.write( "replace a with 4c
\n" ); document.write( "4c = c + 6
\n" ); document.write( "4c - c = 6
\n" ); document.write( "3c = 6
\n" ); document.write( "c = 2 is the units
\n" ); document.write( "then
\n" ); document.write( "a = 4(2)
\n" ); document.write( "a = 8 is the 100's
\n" ); document.write( ":
\n" ); document.write( "then
\n" ); document.write( " b = 14 - 2 - 8
\n" ); document.write( "b = 4 is 10s
\n" ); document.write( ":
\n" ); document.write( "842 is the number
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that works in the statement:
\n" ); document.write( "\"if 594 is subtracted from the number, the number will be reversed.\"
\n" ); document.write( "842 - 594 = 248
\n" ); document.write( "248 = 248
\n" ); document.write( "
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