document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=562121>Question 562121</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve each system using substitution\r<BR>\n" );
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document.write( "y-2x=3<BR>\n" );
document.write( "3x-2y=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364445 by </B><A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><B>TutorDelphia(193)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TutorDelphia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just by adding 2x to both sides of that first equation we get<BR>\n" );
document.write( "y=3+2x\r<BR>\n" );
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document.write( "now we can plug in 3+2x in for y\r<BR>\n" );
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document.write( "3x-2(3+2x)=5<BR>\n" );
document.write( "3x-6-4x=5<BR>\n" );
document.write( "-x-6=5<BR>\n" );
document.write( "-x=11<BR>\n" );
document.write( "x=-11\r<BR>\n" );
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document.write( "plug in -11 for x\r<BR>\n" );
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document.write( "y-2(-11)=3<BR>\n" );
document.write( "y+22=3<BR>\n" );
document.write( "y=-19 </SPAN>\n" );
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