document.write( "Question 562075: solve each system using substitution.\r
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document.write( "4x=3y-2
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document.write( "18=3x+y \n" );
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Algebra.Com's Answer #364442 by TutorDelphia(193)![]() ![]() You can put this solution on YOUR website! First we need to find out what x equals or y equals...it looks like it will be easy to get y alone in the second equation: \n" ); document.write( "4x=3y-2 \n" ); document.write( "18=3x+y\r \n" ); document.write( "\n" ); document.write( "18-3x=y\r \n" ); document.write( "\n" ); document.write( "Now that we know y equals 18-3x I can plug in 18-3x anywhere I see a y \n" ); document.write( "4x=3(18-3x)-2 \n" ); document.write( "Distribute the 3 \n" ); document.write( "4x=54-9x-2 \n" ); document.write( "combine like terms \n" ); document.write( "4x=52-9x \n" ); document.write( "Add 9x to both sides \n" ); document.write( "13x=52 \n" ); document.write( "divide both sides by 13 \n" ); document.write( "x=4 \n" ); document.write( "Now that I know x=4 I can plug it into one of the equations: \n" ); document.write( "4*4=3y-2 \n" ); document.write( "16=3y-2 \n" ); document.write( "Add 2 to both sides \n" ); document.write( "18=3y \n" ); document.write( "divide both sides by 3 \n" ); document.write( "y=6 \n" ); document.write( " |