document.write( "Question 561795: find values of x for 6 sin^2(x) = 3 between [0,2pi] \n" ); document.write( "

Algebra.Com's Answer #364377 by htmentor(1343) $\"\"$ $\"About$

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find values of x for 6 sin^2(x) = 3 between [0,2pi]
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\n" ); document.write( "6 sin^2(x) = 3
\n" ); document.write( "Divide by 6:
\n" ); document.write( "sin^2(x) = 1/2 -> sin^2(x) - 1/2 = 0
\n" ); document.write( "Factor:
\n" ); document.write( " $\"%28sin%28x%29%2B1%2Fsqrt%282%29%29%28sin%28x%29-1%2Fsqrt%282%29%29+=+0\"$
\n" ); document.write( "This gives $\"sin%28x%29+=+1%2Fsqrt%282%29\"$ , $\"-1%2Fsqrt%282%29\"$
\n" ); document.write( "On the interval [0,2pi], the solutions are pi/4,3pi/4,5pi/4,7pi/4 \n" ); document.write( "

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