document.write( "Question 561641: Please help in solving this equation:
\n" ); document.write( "The perimeter of a rectangle is 234 meters, the rectangle is twice as long as it is wide, what are its length and width? \n" ); document.write( "
Algebra.Com's Answer #364359 by ankor@dixie-net.com(22740)\"\" \"About 
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The perimeter of a rectangle is 234 meters, the rectangle is twice as long as it is wide, what are its length and width?
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\n" ); document.write( "I am going to show you how easy this is. Once you understand, you will be able to do this forever.
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\n" ); document.write( "Assuming the side of the rectangle are (L) length and (W) width, the perimeter:
\n" ); document.write( "2L + 2W = 234
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\n" ); document.write( "\"the rectangle is twice as long as it is wide,\", the equation for this statement:
\n" ); document.write( "L = 2W
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\n" ); document.write( "In the first equation, we can replace L with 2W, then we have
\n" ); document.write( "2(2W) + 2W = 234
\n" ); document.write( "4W + 2W = 234
\n" ); document.write( "6W = 234
\n" ); document.write( "Divide both sides by 6
\n" ); document.write( "W = \"234%2F6\"
\n" ); document.write( "W = 39 meters is the width
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\n" ); document.write( "Remember it said the length is twice the width, therefore:
\n" ); document.write( "L = 2(39)
\n" ); document.write( "L = 78 meters is the length
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\n" ); document.write( "Check this by finding the perimeter with these values
\n" ); document.write( "2(78) + 2(39) =
\n" ); document.write( "156 + 78 = 234
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\n" ); document.write( "This is easy stuff, right?\r
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