document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=376148>Question 376148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6x+3y=-3<BR>\n" );
document.write( "-5x+y=20<BR>\n" );
document.write( "6x+3y=-3, -5x+y=20<BR>\n" );
document.write( "add 5 to both ends of 2nd equation<BR>\n" );
document.write( "-5x+5x+y=20+5x<BR>\n" );
document.write( "y = 20+5x<BR>\n" );
document.write( "substitute y in the first equation<BR>\n" );
document.write( "6x+3(20+5x)=-3<BR>\n" );
document.write( "6x+60+15x=-3<BR>\n" );
document.write( "21x=-63<BR>\n" );
document.write( "divide by 21<BR>\n" );
document.write( "x= -63/21<BR>\n" );
document.write( "x= -3<BR>\n" );
document.write( "plug value of x into the second equation<BR>\n" );
document.write( "-5(-3)+y=20<BR>\n" );
document.write( "15+y=20<BR>\n" );
document.write( "y=5\r<BR>\n" );
document.write( "\n" );
document.write( "Solve by substitution method </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364343 by </B><A HREF=/tutors/aboutme.mpl?userid=needhelpfastplease><B>needhelpfastplease(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=needhelpfastplease><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364343\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6x+3y=-3, -5x+y=20<BR>\n" );
document.write( "add 5 to both ends of 2nd equation<BR>\n" );
document.write( "-5x+5x+y=20+5x<BR>\n" );
document.write( "y = 20+5x<BR>\n" );
document.write( "substitute y in the first equation<BR>\n" );
document.write( "6x+3(20+5x)=-3<BR>\n" );
document.write( "6x+60+15x=-3<BR>\n" );
document.write( "21x=-63<BR>\n" );
document.write( "divide by 21<BR>\n" );
document.write( "x= -63/21<BR>\n" );
document.write( "x= -3<BR>\n" );
document.write( "plug value of x into the second equation<BR>\n" );
document.write( "-5(-3)+y=20<BR>\n" );
document.write( "15+y=20<BR>\n" );
document.write( "y=5<BR>\n" );
document.write( "CHECK.... 6*-3+3*5= -3 (remember pemdas so it looks like -18+15=-3)<BR>\n" );
document.write( "......... -5*-3+5=20    (15+5=20)<BR>\n" );
document.write( "ANSWER x=-3 Y=5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );