document.write( "Question 561221: log((x+3)(x-8))+ log((x+3)\(x-8)) = 2\r
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document.write( "I tried but i cannot solve this equation, whose solution is suppose to be x=-13 \n" );
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Algebra.Com's Answer #364331 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! log((x+3)(x-8))+ log((x+3)\(x-8)) = 2 \n" ); document.write( "log((x+3)+log(x-8))+ log((x+3)-log(x-8)) = 2 \n" ); document.write( "log(x-8) cancels out \n" ); document.write( "log(x+3)+log(x+3) = 2 \n" ); document.write( "2log(x+3)=2 \n" ); document.write( "log[(x+3)^2]=2 \n" ); document.write( "convert to exponential form: base(10) raised to log of number(2)=number((x+3)^2) \n" ); document.write( "10^2=(x+3)^2=x^2+6x+9 \n" ); document.write( "x^2+6x-91=0 \n" ); document.write( "(x+13)(x-7)=0 \n" ); document.write( "x+13=0 \n" ); document.write( "x=-13 \n" ); document.write( "or \n" ); document.write( "x-7=0 \n" ); document.write( "x=7 (reject, (x+3)(x-8)>0) \n" ); document.write( " |