document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=54140>Question 54140</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Hello! i tried to solve this one but I am not sure if my answer is correct.<BR>\n" );
document.write( "Chance of getting two 11's    = 2 divided by sample space 21 = 2/21= 0.0952. Thanks!\r<BR>\n" );
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document.write( " Problem:<BR>\n" );
document.write( "Given two six sided dice compute the probability of rolling two 11's in a row. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36431 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are two ways of getting an 11 with 2 dice, (5,6) and (6,5).<BR>\n" );
document.write( "There are 6*6=36 possible sums with two 6 dice.<BR>\n" );
document.write( "So the probability of getting an 11 with two dies is 2/36=1/18.<BR>\n" );
document.write( "Because you're finding the probability of two succesive rolls, you multiply the probability of getting the first 11 * the probabilty of getting the second 11.<BR>\n" );
document.write( "P(11 and 11)=(1/18)(1/18)=1/324=.0031<BR>\n" );
document.write( "Happy Calculating!!! </SPAN>\n" );
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