document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=561329>Question 561329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sqrt(x-6)+3=sqrt(x)<BR>\n" );
document.write( "does this have a real solution?<BR>\n" );
document.write( "first i subtracted the 3 over, squared both sides and ended up with x=(25/4) but when i plug that in, it was not a true statement.<BR>\n" );
document.write( "then i started over and squared both sides like the original problem shows and got the square root equal to a negative so that would be \"no real solution\".<BR>\n" );
document.write( "thank you for looking at this!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364247 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> square roots can be positive or negative\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "25/4 - 6 = 1/4 ___ sqrt(1/4) = ± 1/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-1/2 + 3 = 5/2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "sqrt(25/4) = ± 5/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );