document.write( "Question 561177: What is the minimum value of f(x)=2x^2+5x-1 \n" ); document.write( "
Algebra.Com's Answer #364197 by nerdybill(7384)\"\" \"About 
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f(x)=2x^2+5x-1
\n" ); document.write( "minimun is when x is:
\n" ); document.write( "x = -b/(2a)
\n" ); document.write( "x = -5/(2*2)
\n" ); document.write( "x = -5/4
\n" ); document.write( ".
\n" ); document.write( "substitute back into:
\n" ); document.write( "f(-5/4)=2(-5/4)^2+5(-5/4)-1
\n" ); document.write( "f(-5/4)=2(25/16)+(-25/4)-1
\n" ); document.write( "f(-5/4)=(25/8)+(-25/4)-1
\n" ); document.write( "f(-5/4)=(25/8)+(-50/8)-8/8
\n" ); document.write( "f(-5/4)=-25/8-8/8
\n" ); document.write( "f(-5/4)=-33/8 (this is the minimum value)\r
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