document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=561171>Question 561171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Susan invested part of her 1800 savings at 9% annum and the remainder at 6% per annum. In one year, the 9% investement earned 102 more than the ^% investement. How much did she invest at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #364195 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=364195\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Susan invested part of her 1800 savings at 9% annum and the remainder at 6% per annum. In one year, the 9% investement earned 102 more than the ^% investement. How much did she invest at each rate?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "0.09x - 0.06(1800-x) = 102<BR>\n" );
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document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "9x - 6*1800 + 6x = 10200<BR>\n" );
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document.write( "14x = 21000<BR>\n" );
document.write( "x = $1500 (amt invested at 9%<BR>\n" );
document.write( "1800-x = $300 (amt invested at 6%)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );