document.write( "Question 561044: `During the first part of a trip a canoeist travels 56 miles at a certain speed. the canoeist travels 9 miles on the second part of the trip at 5 mph slower. the total time for the trip is 5 hours. what was the speed on each part of the trip?''.
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Algebra.Com's Answer #364133 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
first part 56 miles
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\n" ); document.write( "speed in first part x mph
\n" ); document.write( "speed second part x-5 mph
\n" ); document.write( "Total rowing time3 hours
\n" ); document.write( "Time first part 56/x
\n" ); document.write( "Time second part 9/(x-5)
\n" ); document.write( "Time first part + time second part = 5 hours
\n" ); document.write( "56/x+9/(x-5)=5
\n" ); document.write( "LCD = x*(x-5)
\n" ); document.write( "multiply the equation by the LCD
\n" ); document.write( "we get
\n" ); document.write( "56*(x-5)+9x=5(x(x-5))
\n" ); document.write( "56x-280 +9x=5x^2+-25x
\n" ); document.write( "90x-280 =5x^2
\n" ); document.write( "5X^2-90 x+280 = 0
\n" ); document.write( "5 x^2+ -90 x+ 280 =
\n" ); document.write( "/ 5
\n" ); document.write( "x^2-18x+56 \r
\n" ); document.write( "\n" ); document.write( "x^2-14x-4x+56=0
\n" ); document.write( "x(x-14)-4(x-14)=0
\n" ); document.write( "(x-14)(x-4)=0\r
\n" ); document.write( "\n" ); document.write( "first part speed = 14 mph
\n" ); document.write( "second part 14-5 =9 mph\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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