document.write( "Question 560968: During the first part of a trip a canoeist travels 41 miles at a certain speed. the canoeist travels 8 miles on the second part of the trip at 5 mph slower. the total time for the trip is 3 hours. what was the speed on each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #364099 by mananth(16946)\"\" \"About 
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first part 41 miles
\n" ); document.write( "second part 8 miles
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\n" ); document.write( "speed in first part xmph
\n" ); document.write( "speed second part x-5 mph
\n" ); document.write( "Total rowing time3 hours
\n" ); document.write( "Time first part 41/x
\n" ); document.write( "Time second part8/(x-5)
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\n" ); document.write( "Time first part + time second part = 3 hours
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\n" ); document.write( "41/x + 8/(x-5) =3
\n" ); document.write( "LCD = x*(x-5 )
\n" ); document.write( "multiply the equation by the LCD
\n" ); document.write( "we get
\n" ); document.write( "41*(x-5 )+8x=3(x(x-5))
\n" ); document.write( "41x-205 +8x=3X^2-15
\n" ); document.write( "64x-205 =3X^2
\n" ); document.write( "3X^2-64x+205= 0
\n" ); document.write( "3 X^2+ -64 x+ 205 =
\n" ); document.write( "Find the roots of the equation by quadratic formula
\n" ); document.write( "a= 3 b= -64 c= 205 b^2-4ac= 4096 - -2460
\n" ); document.write( "b^2-4ac= 1636
\n" ); document.write( "\"sqrt%28%091636%09%29\"= 40.45
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=( 64 + 40.45 )/ 6
\n" ); document.write( "x1= 17.41
\n" ); document.write( "x2=( 64 -40.45 ) / 6
\n" ); document.write( "x2= 3.93
\n" ); document.write( "Ignore negative value
\n" ); document.write( "x = 17.41 mph \r
\n" ); document.write( "\n" ); document.write( "first part speed = 17.41 mph
\n" ); document.write( "second part speed = 12.41 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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