document.write( "Question 560968: During the first part of a trip a canoeist travels 41 miles at a certain speed. the canoeist travels 8 miles on the second part of the trip at 5 mph slower. the total time for the trip is 3 hours. what was the speed on each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #364099 by mananth(16946)![]() ![]() You can put this solution on YOUR website! first part 41 miles \n" ); document.write( "second part 8 miles \n" ); document.write( " \n" ); document.write( "speed in first part xmph \n" ); document.write( "speed second part x-5 mph \n" ); document.write( "Total rowing time3 hours \n" ); document.write( "Time first part 41/x \n" ); document.write( "Time second part8/(x-5) \n" ); document.write( " \n" ); document.write( "Time first part + time second part = 3 hours \n" ); document.write( " \n" ); document.write( "41/x + 8/(x-5) =3 \n" ); document.write( "LCD = x*(x-5 ) \n" ); document.write( "multiply the equation by the LCD \n" ); document.write( "we get \n" ); document.write( "41*(x-5 )+8x=3(x(x-5)) \n" ); document.write( "41x-205 +8x=3X^2-15 \n" ); document.write( "64x-205 =3X^2 \n" ); document.write( "3X^2-64x+205= 0 \n" ); document.write( "3 X^2+ -64 x+ 205 = \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( "a= 3 b= -64 c= 205 b^2-4ac= 4096 - -2460 \n" ); document.write( "b^2-4ac= 1636 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 64 + 40.45 )/ 6 \n" ); document.write( "x1= 17.41 \n" ); document.write( "x2=( 64 -40.45 ) / 6 \n" ); document.write( "x2= 3.93 \n" ); document.write( "Ignore negative value \n" ); document.write( "x = 17.41 mph \r \n" ); document.write( "\n" ); document.write( "first part speed = 17.41 mph \n" ); document.write( "second part speed = 12.41 mph \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |