document.write( "Question 560930: Please help me solve this system using the method of substitution. I would like the steps to know how it's done. Thank you.
\n" ); document.write( ".5x+2.2y=9
\n" ); document.write( "6x+.4y=22
\n" ); document.write( "

Algebra.Com's Answer #364081 by stanbon(75887)\"\" \"About 
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5x+2.2y=9
\n" ); document.write( "6x+.4y=22
\n" ); document.write( "----
\n" ); document.write( "Solve the 1st for \"x\":
\n" ); document.write( "x = (9-2.2y)/5
\n" ); document.write( "----
\n" ); document.write( "Substitute for \"x\" and solve for \"y\":
\n" ); document.write( "6[(9-2.2y)/5] + 0.4y = 22
\n" ); document.write( "------------------------------
\n" ); document.write( "(54 - 13.2y)/5 + 0.4y = 22
\n" ); document.write( "Multiply thru by 5 to get:
\n" ); document.write( "54-13.2y + 2y = 110
\n" ); document.write( "-11.2y = 56
\n" ); document.write( "y = -5
\n" ); document.write( "---
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x = (9-2.2y)/5
\n" ); document.write( "x = (9-2.2*-5)/5
\n" ); document.write( "x = 4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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