document.write( "Question 560930: Please help me solve this system using the method of substitution. I would like the steps to know how it's done. Thank you.
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document.write( ".5x+2.2y=9
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document.write( "6x+.4y=22 \n" );
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Algebra.Com's Answer #364081 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 5x+2.2y=9 \n" ); document.write( "6x+.4y=22 \n" ); document.write( "---- \n" ); document.write( "Solve the 1st for \"x\": \n" ); document.write( "x = (9-2.2y)/5 \n" ); document.write( "---- \n" ); document.write( "Substitute for \"x\" and solve for \"y\": \n" ); document.write( "6[(9-2.2y)/5] + 0.4y = 22 \n" ); document.write( "------------------------------ \n" ); document.write( "(54 - 13.2y)/5 + 0.4y = 22 \n" ); document.write( "Multiply thru by 5 to get: \n" ); document.write( "54-13.2y + 2y = 110 \n" ); document.write( "-11.2y = 56 \n" ); document.write( "y = -5 \n" ); document.write( "--- \n" ); document.write( "Solve for \"x\": \n" ); document.write( "x = (9-2.2y)/5 \n" ); document.write( "x = (9-2.2*-5)/5 \n" ); document.write( "x = 4 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " \n" ); document.write( " |