document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=560647>Question 560647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It takes Jake, 14h to repair a car’s transmission. After he had worked for 7 h, Alice began to help him. Together, they finished the job in 3 more hours. How long would it take Alice to do the job alone?\r<BR>\n" );
document.write( "\n" );
document.write( "I attempted to do this problem like I did the other one's by assigning a variable to the unknown amout of time worked by Alice. Then I got stuck when I tried to find the rate for both. And I think I'm supposed to subtract somewhere. Any help would be appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #363993 by </B><A HREF=/tutors/aboutme.mpl?userid=itsmers123nj><B>itsmers123nj(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=itsmers123nj><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=363993\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = time Alice works alone.<BR>\n" );
document.write( "14h = time Jake works alone.<BR>\n" );
document.write( "Jake: 7+3 = 10(1/14) = 10/14 = 5/7<BR>\n" );
document.write( "Alice: 1/x(3)=3/x<BR>\n" );
document.write( "SOLUTION: 5/7+3/x=1 (LCM = 14x)<BR>\n" );
document.write( "14n(5/7+3/x)=1(14n)->10x+42=14x-> x = 21/2 = 10.5<BR>\n" );
document.write( "ANSWER: It would take Alice 10h 30m to repair the transmission if she works alone.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );