document.write( "Question 560610: Write a quadratic function whose graph has the given characteristics: x-intercepts (-1,0),(7,0) and a point on the graph: (3,2).
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document.write( "I tried making an equation using both intercepts.
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document.write( "x=-1 x=7
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document.write( "x+1=0 x-7=0
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document.write( "(x+1)(x-7)=0
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document.write( "x^2-6x-7=0
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document.write( "So far I have this equation, but I don't know how to make it go through the point (3,2). If anyone could please help me, I would greatly appreciate it. \n" );
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Algebra.Com's Answer #363990 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! you know that the x-intercepts are the roots of the function\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the axis of symmetry lies midway between the roots ___ x = (-1 + 7) / 2 ___ x = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the given point is on the axis of symmetry, so it is the vertex\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using the vertex form ___ y = a(x - 3)^2 + 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "plug in one of the intercepts to find the value of a ___ 0 = a(7 - 3)^2 + 2 \n" ); document.write( " |